P.H. Trinh

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projects_divergentphysics [2020/04/10 14:09]
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projects_divergentphysics [2020/04/10 14:11] (current)
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 V(x) = \frac{1}{2} x^2. V(x) = \frac{1}{2} x^2.
 $$ $$
-You learn that the permissible energies take discrete values like $E_n = n + 1/2$. In an effort to understand how this can be generalised,​ you might try to perturb the potential ​that you have above so that it includes a small higher-order term, like this:+You learn that the permissible energies take discrete values like $E_n = (n + 1/2)$. In an effort to understand how this can be generalised,​ you might try to perturb the potential that it includes a small higher-order term, like this:
 $$ $$
 V(x) = \frac{1}{2} x^2 + \lambda x^4. V(x) = \frac{1}{2} x^2 + \lambda x^4.